pyspark.RDD.subtractByKey¶
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RDD.subtractByKey(other: pyspark.rdd.RDD[Tuple[K, Any]], numPartitions: Optional[int] = None) → pyspark.rdd.RDD[Tuple[K, V]]¶ Return each (key, value) pair in self that has no pair with matching key in other.
Examples
>>> x = sc.parallelize([("a", 1), ("b", 4), ("b", 5), ("a", 2)]) >>> y = sc.parallelize([("a", 3), ("c", None)]) >>> sorted(x.subtractByKey(y).collect()) [('b', 4), ('b', 5)]